Question

e2-10e+9=0 Factorise as negative values inside​

Answer 1

Answer:

This relationship is always true: If you get a negative value inside the square root, then there will be no real number solution, and therefore no x-intercepts. In other words, if the the discriminant (being the expression b2 – 4ac) has a value which is negative, then you won't have any graphable zeroes.

Answer 2

e^2-10e+9

e^2-9e-e+9

e(e-9)-1(e-9)

(e-9)(e-1)

❣️Thnx buddy....!!❣️