Question

Each angle of a quadrilateral is larger than the nearest smaller angle by 30°.Find all the angles of the quadrilateral​

Answer 1

Answer:

Let the smaller angle be s, then the larger angle will be s+30

s+(s+30)+s+(s+30)=360

4s+60=360

4s=360-60=300

s=300/4=75

Angles are 75, 105, 75 and 105

This condition is not possible for all quadrilateral