Each angle of a rectangle is bisected. Let P,Q,R and S be the points of intersection of the pairs of bisectors adjacent to the same side of the rectangle. Then PQRS is a
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ABCD is a given rectangle.
AS , DS , BQ, CQ is angle bisector of angle A, angle D, angle B, angle C respectively.
In triangle ASD
Angle DAS= ADS =45 degree
So angle ASD =180-(45+45) = 90 degree
angle RSP = angle ASD =90 degree (vertically opposite angle )
Similarly for triangle BQC
angle QBC = angle BCQ = 45 degrees.
Hence, angle BQC = 180-(45+45) = 90 degree.
angle BQC = angle RQP = 90 degree ( vertically opposite angle )
Now, since AB is parallel to CD and DR and PB are angle bisectors so DR becomes parallel to PB. And angle RSP = angle RQP = 90 degree.
So, PS becomes parallel to QR.
This proves that PQRS is a rectangle.
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