Question

each base angle of an isosceles triangle 15° more than its vertical angle. Find each angle of the triangle​

Answer 1

Answer:

Let vertical angle of the isosceles triangle = x°

∴ Each base angle = x + 15°

X + 15° + x + 15° + x° = 180°

(Sum of angles of a triangle)

⇒ 3x + 30° = 180°                                 

⇒ 3x = 180° - 30° = 150°

∴ x = 150°/3 = 50°

Hence vertical angle = 50°

 and each base angle = 50° + 15°  = 65°

Answer 2

Answer:

Let the vertical angle of the isosceles triangle = X⁰

According to question

Then the each base angle of the triangle is = X⁰+15⁰

As we know the sum of all three angles in a triangle is 180⁰

=> X⁰ + X⁰+15⁰+ X⁰+15⁰ = 180⁰

=> 3X⁰ + 30⁰ = 180⁰

=> 3X⁰ = 180⁰- 30⁰= 150⁰

=> X⁰ = 150⁰/3= 50⁰

And X⁰+15⁰= 50⁰+15⁰ = 65⁰

So the vertical angle of the triangle

is 50⁰ and the base angled are 65⁰.