each base angle of an isosceles triangle in four times the vertex angle find all the angles of the triangle
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Answer:
20,80
Step-by-step explanation:
let the vertex angle be v
so each base angle of an isosceles triangle = 4v
ATP,
4v+4v+v = 180
9v = 180
v = 180/9 = 20
vertex angle = v = 20
each base angle of an isosceles triangle = 4v = 4(20) = 80
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