each base angle of an isosceles triangle is 15 degree more than its vertical angle.find each angle of the triangle.
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Let the base angle Be “A” And “B” and the vertical angle C
for an Isosceles A=B
Sum of internal angles of a triangle =180°
2(C+15)+C=180°
3C+30= 180°
C= 50°
A=B=65°
Hope this Answer Is helpful.
for an Isosceles A=B
Sum of internal angles of a triangle =180°
2(C+15)+C=180°
3C+30= 180°
C= 50°
A=B=65°
Hope this Answer Is helpful.
throwathigh:
pls choose a brainliest answer!
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