Math, asked by taqdeersimratpalsing, 6 months ago

Each base angle of an isosceles triangle is 15° more than its vertical angle. Find ench angle of the triangle​

Answers

Answered by maindbharti484
0

Answer:

Answer:Consider the vertical angle of the isosceles triangle =x

Answer:Consider the vertical angle of the isosceles triangle =x ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a triangle

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘ 3x=180–30=150

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘ 3x=180–30=150 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘ 3x=180–30=150 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘ 3x=180–30=150 ∘ x=150/3=50

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘ 3x=180–30=150 ∘ x=150/3=50 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘ 3x=180–30=150 ∘ x=150/3=50 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘ 3x=180–30=150 ∘ x=150/3=50 ∘ Therefore, vertical angle =50

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘ 3x=180–30=150 ∘ x=150/3=50 ∘ Therefore, vertical angle =50 ∘

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘ 3x=180–30=150 ∘ x=150/3=50 ∘ Therefore, vertical angle =50 ∘ and each base angle =50+15=65

Answer:Consider the vertical angle of the isosceles triangle =x ∘ Here each base angle=x+15 ∘ In a trianglex+15 ∘ +x+15 ∘ +x=180 ∘ By further calculation3x+30 ∘ =180 ∘ 3x=180–30=150 ∘ x=150/3=50 ∘ Therefore, vertical angle =50 ∘ and each base angle =50+15=65 ∘

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