Question

Each base of an isosceles triangle is 15 degree more than its vertical angle.Find each angle of the triangle...Plzzz answer

Answer 1

HEYA MATE, HERE IS UR ANSWER

$\huge\boxed{\red {\bold {ANSWER}}}$

Let the vertex angle be x degrees .

Then each base angle =x+15

$\underline{\blue{\bold {By \:angle\:Sum\: property\:of \:triangle}}}$

X+x+15+x+15=180

3x+30=180

3x=180-30

3x=150

x=150/3

x=50 degree

Therefore

$\underline{\green{\bold{Vertex \:angle}}}$=50 degrees

$\underline{\green{\bold{Base\:angle}}}$=50+15

=65 degrees.

$\mathbb{Be\:Brainly }$

Answer 2

Answer:

This is answer..

Step-by-step explanation:

I hope its helpful..