Each child born to a particular set of parents has a probability of 0.25 of having blood type O. If these parents have 5 children. What is the probability that a.Exactly two of them have blood type Ob.At most 2 have blood type Oc.At least 4 have blood type Od.2 do not have blood type O
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Since each child has a 0.25 chance of inheriting type O blood, we'd expect one-fourth of the 5 children to have this blood type. That is, µX = 5(0.25) = 1.25. This method can be used to find the mean of any binomial random variable with parameters n and p.
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