each edge of a cube is increase by 50% find the percentage increase in the surface area if the cube
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side increase 50 %
before increase
side =a
after increase. A = 3/2 a
surface area s.a =6 a^2
SA = 6 [3/2a]^2=6[9/4 ]a^2
ineasing percent =[SA-sa][100]/sa
=(54/4 a^2 -6a^2)(100)/6a^2==
=(13.5 -6)100/6
=7.5(100)6=750/6
=125%
before increase
side =a
after increase. A = 3/2 a
surface area s.a =6 a^2
SA = 6 [3/2a]^2=6[9/4 ]a^2
ineasing percent =[SA-sa][100]/sa
=(54/4 a^2 -6a^2)(100)/6a^2==
=(13.5 -6)100/6
=7.5(100)6=750/6
=125%
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125 percent
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