each edge of a cube is increased by 50%.find the percentage increased in the surface area?
Answers
here is your answer >>>
The general formula for a surface area of a cube is 6(a)^2,
where, a is the side!
Now, the side is increased by 50%! .
then, the side will be
>>>
a + (50/100)a
a + (a/2)
3a/2!
This is the increased side,
original is 'a'!
Now, we have to find the percent increase!
The surface area of the increased edge cube is !
>>>
(6)(3a/2)^2
(6)(9a^2/4)
27a^2/2 is the surface area!
Re surface area is (6)(a)^2!
increased surface area is 27a^2/2 - 6a^2
=> 15a^2 / 2!
Increased percent is the difference/original (100)
so,
(15a^2 / 6a^2 ) (100)
=> a^2 will be cancelled!
(15/6)(100)!
(5/2)(100)
=> 250% increase is the answer!
Hope my answer helps!
Answer:
125 %
Step-By-Step Explanation:
In such questions, the first step of all individuals should be assuming the side to be a variable.
Let the measure of each edge of the cube be ' x ' cm.
Total surface area of the cube = 6 ( x ) ^ 2
Total surface area of the cube = 6 * x ^ 2
Total surface area of the cube = 6x ^ 2 cm²
Now when each edge is increased by 50 %,
Measure of the edge of new cube = x + 50 % of x
Measure of the edge of new cube = x + 50x / 100
Measure of the edge of new cube = x + x / 2
Measure of the edge of new cube = ( 3x / 2 ) cm
Total surface area of the new cube = 6 * ( 3x / 2 ) ^ 2
Total surface area of the new cube = 6 * ( 9x^2 / 4 )
Total surface area of the new cube = 54x ^ 2 / 4
Total surface area of the new cube = 13.5 x ^ 2 cm²
Increase in the total surface area = 13.5 x ^ 2 - 6 x ^ 2
Increase in the total surface area = 7.5 x ^ 2 cm²
Now,
Percentage increase in the total surface area = ( Increase in total surface area * 100 ) / Initial total surface area of the cube
Percentage increase in the total surface area = ( 7.5 x ^ 2 * 100 ) / 6 x ^ 2
Percentage increase in the total surface area = 750 x ^ 2 / 6 x ^ 2
Percentage increase in the total surface area = 750 / 6
Percentage increase in the total surface area = 375 / 3
Percentage increase in the total surface area = 125 %