Math, asked by rpdas023, 11 months ago

each edge of a cube is increased by 50 % . the percent of increase in the surface area of the cube is? ​

Answers

Answered by mpneelamporwal
9

Step-by-step explanation:

let original length of egde be x

then increase is

x×50/100

x/2

new edge

x/2+x

3x/2

now surface area with new edge

6(3x/2)²

6×9x²/4

3×9x²/2

27x²/2 ---------1

now surface area with original edge

6x² -------------2

now 1-2 is the increased surface area

27x²/2-6x²

27x²-12x²/2

15x²/2

now percentage increase is

15x²/2=6x²×y/100 ( y is percentage increase)

15x²=6x²×y/50

15×50/6= y

15×25/3= y

5×25 =y

125 =y

hence increase is 125%

THANK YOU

Similar questions