each edge of a cube is increased by 50 % . the percent of increase in the surface area of the cube is?
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Step-by-step explanation:
let original length of egde be x
then increase is
x×50/100
x/2
new edge
x/2+x
3x/2
now surface area with new edge
6(3x/2)²
6×9x²/4
3×9x²/2
27x²/2 ---------1
now surface area with original edge
6x² -------------2
now 1-2 is the increased surface area
27x²/2-6x²
27x²-12x²/2
15x²/2
now percentage increase is
15x²/2=6x²×y/100 ( y is percentage increase)
15x²=6x²×y/50
15×50/6= y
15×25/3= y
5×25 =y
125 =y
hence increase is 125%
THANK YOU
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