Each edge of a regular tetrahedron is 3 cm then the volume is
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volume of regular tetrahedron = a³/6√2
where a = 3 cm is the edge
thus volume = 3³/6√2 = 9√2/4 = 2.25*1.414 = 3.1815 cm^3
where a = 3 cm is the edge
thus volume = 3³/6√2 = 9√2/4 = 2.25*1.414 = 3.1815 cm^3
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