each edge of a square pyramid is 2 a units find then height slant height lateral surface area total surface area volume
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slant height = √3
lateral surface area = 4* area of triangles= 4*(√3/4)(2*2)= 4√3(a2)
total surface are = area of 4 triangles+area of square= 4√3+ (2*2)= 4(1+√3)(a2)
height= √2a
Volume = 1/3(area of base)(height)= (1/3)(4)(√2)a3
= (4√2)3(a3)
lateral surface area = 4* area of triangles= 4*(√3/4)(2*2)= 4√3(a2)
total surface are = area of 4 triangles+area of square= 4√3+ (2*2)= 4(1+√3)(a2)
height= √2a
Volume = 1/3(area of base)(height)= (1/3)(4)(√2)a3
= (4√2)3(a3)
Rutwika:
But I need the process
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