Each edge of cube is increased by 50%. Find the increase percent in surface area.
Answers
Answered by
17
Let the original side of cube be 'a'
Therefore, Original Surface area = 6a²
Now,
Increase in side = 50%
Therefore,
Side = a(50% of a)
= a(50/100 x a)
= a + a/2
= 2a+a/2
= 3a/2
New Surface Area = 6a² = 6 x 3a/2 x 3a/2 = 27a²/2
It's increase Surface Area= New Area-Original area
= 27a²/2-6a²
= 27a²-12a²/2 = 15a²/2
Therefore,
Percentage of Increase in Surface Area= (15a²/2/6a² x 100)%
= (1.25 x 100)%
= 125 %
Therefore, Original Surface area = 6a²
Now,
Increase in side = 50%
Therefore,
Side = a(50% of a)
= a(50/100 x a)
= a + a/2
= 2a+a/2
= 3a/2
New Surface Area = 6a² = 6 x 3a/2 x 3a/2 = 27a²/2
It's increase Surface Area= New Area-Original area
= 27a²/2-6a²
= 27a²-12a²/2 = 15a²/2
Therefore,
Percentage of Increase in Surface Area= (15a²/2/6a² x 100)%
= (1.25 x 100)%
= 125 %
Answered by
25
Let the original side of the cube be x units.
So, the Total Surface Area previously = 6x^2
Now, when side is increased by 50%
New side = x + 50% of x.
Total Surface area of new cube =
Increase in total surface area = New area - older area
27 x^2 -12x^2 /2
15x^2/2
Percentage increase =
5/4 ×100
= 125%
So, the Total Surface Area previously = 6x^2
Now, when side is increased by 50%
New side = x + 50% of x.
Total Surface area of new cube =
Increase in total surface area = New area - older area
27 x^2 -12x^2 /2
15x^2/2
Percentage increase =
5/4 ×100
= 125%
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