Question

Each equal side of an equilateral triangle is 13 cm each find it's area and its altitude

Answer 1

Answer:

$\huge\bold\star\red{Answer}\star$

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

$\huge\bold{\underline{\underline{{Question:-}}}}$

Each equal side of an equilateral triangle is 13cm. Find its area and altitude.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Given:-

• each side of an equilateral triangle is 13cm

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

To find:-

• area and altitude of the triangle

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\huge\bold{\underline{\underline{{Solution:-}}}}$

Formula for finding area of triangle:-

❶1/2×base×altitude

❷√s(s-a)(s-b)(s-c) where s is semi perimeter

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

°•°sides are given,we will use the second formula.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Now,let sides are a,b and c respectively

•°•a=b=c=13cm

S=a+b+c/2

=13+13+13/2

=39/2

=19.5cm

now ,area of the triangle=√s(s-a)(s-b)(s-c) =√19.5(19.5-13)(19.5-13)(19.5-13)

=√19.5×6.5×6.5×6.5

=6.5√176.75cm^2

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

hence the area of the triangle is 6.5√176.75cm^2

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

Answer 2

$<svg width="200" height="300" viewBox="0 0 100 100">\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <path fill="orange" d="M92.71,7.27L92.71,7.27c-9.71-9.69-25.46-9.69-35.18,0L50,14.79l-7.54-7.52C32.75-2.42,17-2.42,7.29,7.27v0 c-9.71,9.69-9.71,25.41,0,35.1L50,85l42.71-42.63C102.43,32.68,102.43,16.96,92.71,7.27z"></path>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \, \ <animateTransform \ \textless \ br /\ \textgreater \ attributeName="transform" \ \textless \ br /\ \textgreater \ type="scale" \ \textless \ br /\ \textgreater \ values="1; 1.5; 1.25; 1.5;1.75;1.75 ;1.25; 1;" \ \textless \ br /\ \textgreater \ dur="2s" \ \textless \ br /\ \textgreater \ repeatCount="20"> \ \textless \ br /\ \textgreater \ </animateTransform>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ </svg>$

$\huge{ \underline{ \bold{ᴀɴsᴡᴇʀ....{ \heartsuit}}}}$

Formula for finding area of triangle:-

❶1/2×base×altitude

❷√s(s-a)(s-b)(s-c) where s is semi perimeter

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

°•°sides are given,we will use the second formula.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Now,let sides are a,b and c respectively

•°•a=b=c=13cm

S=a+b+c/2

=13+13+13/2

=39/2

=19.5cm

now ,area of the triangle=√s(s-a)(s-b)(s-c) =√19.5(19.5-13)(19.5-13)(19.5-13)

=√19.5×6.5×6.5×6.5

=6.5√176.75cm^2

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

hence the area of the triangle is 6.5√176.75cm^2