Question

Each equal side of an equilateral triangle is 13 cm each find it's area and its altitude​

Answer 1

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Formula for finding area of triangle:-

❶1/2×base×altitude

❷√s(s-a)(s-b)(s-c) where s is semi perimeter

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°•°sides are given,we will use the second formula.

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Now,let sides are a,b and c respectively

•°•a=b=c=13cm

S=a+b+c/2

=13+13+13/2

=39/2

=19.5cm

now ,area of the triangle=√s(s-a)(s-b)(s-c) =√19.5(19.5-13)(19.5-13)(19.5-13)

=√19.5×6.5×6.5×6.5

=6.5√176.75cm^2

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hence the area of the triangle is 6.5√176.75cm^2

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Answer 2

here is your answer my deaf friend plz mark my answer as the brainless answer...

A≈73.18cm²

a Side

13 cm

Solution:

A=3

4a2=3

4·132≈73.17915cm²