Question

Each equal side of an isosceles right triangle is x find its area

Answer 1

Answer:

Step-by-step explanation:

1/2*B*H=Area of a triangle

=1/2*x*x

=$\frac{x^2}{2}$

hope it helps..

Answer 2

Answer:

each equal side of an isosceles right angled triangle is x, so its area is equal to X^2 /2



Step-by-step explanation:

we have given in the Question

two sides of an isosceles triangle as =

Now we know that the area of an isosceles triangle is equal to 1/2 BASE × HEIGHT

1/2 × X× X

=1/2 X^2

=X^2/2 which is required answer and the area of Isosceles Right angled triangle

The area of isosceles right triangle follows the general formula of area of a triangle that is (1/2) × Base × Height. For example In any ∆ABC with side lengths AB= BC = x where AB represents the height and BC represents the base, the area of isosceles right triangle formula is given by 1/2 × AB × BC = x2/2 square units.