Question

Each interior angle of a regular polygon is
108°. What is the measure of each angle of a
regular polygon having double the number of sides as the first polygon​

Answer 1

Step-by-step explanation:

Each interior angle = (n-2) * 180 / n

gn, 108 = (n-2) *180 / n

108 n = 180 n - 360

180 n - 108 n = 360

72 n = 360

Therefore n = 5

Double the no of sides as the first polygon

= 2 * n

= 2 * 5

= 10

Each interior angle = (n - 2) * 180 / n

= (10 - 2) * 180 / 10

= 8* 180/ 10

Answer = 144

Answer 2

Each interior angle = (n-2) * 180 / n

gn, 108 = (n-2) *180 / n

108 n = 180 n - 360

180 n - 108 n = 360

72 n = 360

Therefore n = 5

Double the no of sides as the first polygon

= 2 * n

= 2 * 5

= 10

Each interior angle = (n - 2) * 180 / n

= (10 - 2) * 180 / 10

= 8* 180/ 10

Answer = 144

please give me brainliest