Each interior angle of a regular polygon is double of its exterior angle. Find the
number of sides in the polygon.
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Answer:
ANSWER
Let the number of sides in the polygon is n
Let the measure of exterior angles be x respectively.
⇒ measure of interior angle =2x
∴n×2x=(2n−4)×90°
⇒nx=(n−2)×90°.....(i)
Again, we know that,
nx=360°
(n−2)×90°=360°[From(i)]
n−2=4
⇒n=6
Hence the number of sides in the polygon are 6.
this is your answer
Answered by
6
Answer:
Let the number of sides in the polygon is n
Let the measure of exterior angles be x respectively.
⇒ measure of interior angle =2x
∴n×2x=(2n−4)×90°
⇒nx=(n−2)×90°.....(i)
Again, we know that,
nx=360°
(n−2)×90°=360°[From(i)]
n−2=4
⇒n=6
Hence the number of sides in the polygon are 6.
Hope this is helpful for you.
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