Math, asked by venkatK24470, 4 months ago

Each interior angle of a regular polygon is double of its exterior angle. Find the
number of sides in the polygon.
of

Answers

Answered by Anonymous
12

Answer:

ANSWER

Let the number of sides in the polygon is n

Let the measure of exterior angles be x respectively.

⇒ measure of interior angle =2x

∴n×2x=(2n−4)×90°

⇒nx=(n−2)×90°.....(i)

Again, we know that,

nx=360°

(n−2)×90°=360°[From(i)]

n−2=4

⇒n=6

Hence the number of sides in the polygon are 6.

this is your answer

Answered by ꜱᴄʜᴏʟᴀʀᴛʀᴇᴇ
6

Answer:

Let the number of sides in the polygon is n

Let the measure of exterior angles be x respectively.

⇒ measure of interior angle =2x

∴n×2x=(2n−4)×90°

⇒nx=(n−2)×90°.....(i)

Again, we know that,

nx=360°

(n−2)×90°=360°[From(i)]

n−2=4

⇒n=6

Hence the number of sides in the polygon are 6.

Hope this is helpful for you.

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