each interior angle of regular polygon is 'a' times of its exterior angle. Find , in terms of a, the number of sides in the polygon
Answers
Answered by
1
In a polygon,
interior angle + exterior angle = 180
if the interior angle is a times the exterior angle,
exterior angle = x
interior angle = ax
sum = x + ax = 180
⇒x(1+a) = 180
⇒ x = 180/(1+a)
Also the sum of exterior angles is 360.
If a polygon has n sides, it will have n exterior angles
Number of sides = 2(1+a)
interior angle + exterior angle = 180
if the interior angle is a times the exterior angle,
exterior angle = x
interior angle = ax
sum = x + ax = 180
⇒x(1+a) = 180
⇒ x = 180/(1+a)
Also the sum of exterior angles is 360.
If a polygon has n sides, it will have n exterior angles
Number of sides = 2(1+a)
Anonymous:
hello sum of interior angles of a polygon is 360 . SO please edit your solution !!!
Answered by
0
In terms of a, number of sides = 2(1+a)=2a+2
Similar questions