Math, asked by tarunsoni899, 1 year ago

each interior angle of regular polygon is 'a' times of its exterior angle. Find , in terms of a, the number of sides in the polygon

Answers

Answered by TPS
1
In a polygon, 
interior angle + exterior angle = 180

if the interior angle is a times the exterior angle,
exterior angle = x
interior angle = ax
sum = x + ax = 180
⇒x(1+a) = 180
⇒ x = 180/(1+a)

Also the sum of exterior angles is 360.
If a polygon has n sides, it will have n exterior angles

n*x=360 \\  \\ n= \frac{360}{x}  \\  \\ n= \frac{360}{( \frac{180}{1+a} )} = \frac{360*(1+a)}{180} =2(1+a)

Number of sides = 2(1+a)


Anonymous: hello sum of interior angles of a polygon is 360 . SO please edit your solution !!!
TPS: have you heard of a triangle, pentagon or hexagon?
Anonymous: oops sorry I mean sum of interior angles of a polygon is 180 degrees !!!
Anonymous: oops sorry u are right !!!
TPS: 180 degrees is for triangle only
TPS: if a regular polygon has n sides, then sum of internal angles is 180(n-2)
Anonymous: yepp!!!
TPS: but sum of exterior angles remain 360.
Anonymous: i know all these things thanks for your concern !!!!
Anonymous: enjoy ur time !!! :)
Answered by Anonymous
0
In terms of a, number of sides = 2(1+a)=2a+2
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