Math, asked by chilacool2, 1 year ago

each letter of the word MATHMATICS is written on a separate card.
jake picks one card at random.what is the probability that the letter is :

a}M
b}not T
c}a vowel
d}not a vowel
e}X
f}in the word CHANCE?


chilacool2: i forgot to write the vowels are a/e/l/o and u please help me

Answers

Answered by kusum2003kin
4

Answer:


Step-by-step explanation:

a.2/10=1/5=ans

b.8/10=4/5=ans

c.3/10=ans

d.7/10=ans

e.0=ans

f.4/10=2/5=ans

Answered by nagpurkaru27
1

Answer:

a] 2/11

b]9/11

c]4/11

d]7/11

e]0/11

f]5/11

Step-by-step explanation:

S = {M,A,T,H,E,M,A,T,I,C,S}.... n(S)= 11

a)  let event A be the event where jake picks the card and that card is 'M'

A = {M,M}.... n(A) = 2

HENCE.... P(A)= n(A)/n(S)

hence...P(A)=2/11.......................[1]

b) let event B be the event where picked card is not T

B = {M,A,H,E,M,A,I,C,S}

n(B) = 9

P(B) =n(B)/n(S)

P(B) = 9/11

c) let C be the event where the card has a vowel

C = {A,E,A,I}

n(C)= 4

P(C) = n(C) / n(S)

P(C)= 4/11

d) let D be the event where the card does not bear a vowel

D ={M,T,H,M,T,C,S}

n(D)=7

P(D)= n(D) /n(S)

P(D) = 7/11

e) let E be the event where the card has X on it

E = {}

n(E)= 0

P(E) = n(E)/n(S)

P(E) = 0/11

f) let F be the event where the card has the alphabet from word CHANCE.

F = {C,H,A,C,E}

n(F) = 5

P(F) = n(F)/n(S)

P(F)= 5/11

hence this is the answers with COMPLETE SOLUTION.....



































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