Question

Each of A &B tosses 2coins , what is the probability that they get equal number of heads ?​

Answer 1

Answer:

1/2 hope it's correct brainlist

Answer 2

Let X be the number of heads obtained by A and Y be the number of heads

obtained by B. Note that both X and Y are binomial variate with

parameters n=3 and p=1/2.

Probability that both A and B obtain the same number of heads is

=P(X=0)P(Y=0)+P(X=1)P(Y=1)+P(X=2)P(Y=2)+P(X=3)P(Y=3)

$= [3_{C_0}( \frac{1}{2} ) {}^{3}] {}^{2} + [3_{C_1}( \frac{1}{2} ) {}^{3}] {}^{2} + [3_{C_2}( \frac{1}{2} ) {}^{3}] {}^{2} + [3_{C_3}( \frac{1}{2} ) {}^{3}] {}^{2}$

$= ( \frac{1}{2} ) {}^{6} [1+9 + 9 + 1] = \frac{20}{64} = \frac{5}{16}$