Each of A and B tosses two coins. What is the probability that they get equal number of heads?
Answers
Answered by
0
Answer:
316
516
416
616
Answer :
B
Solution :
If both get one head then it is 14×14
and if both get two heads then it is 12×12
⇒ Prob(getting same number of heads) =14×14+12×12
=116+14=516
Step-by-step explanation:
indranil97:
Wrong Answer
hey what
I asked for probability which cannot be greater than 1. What kind of probability is 516. duh?
For a toss of 3 coins,
S = { HHH, HHT, HTH, THH, TTH,
THT, HTT, TTT }
So, n(S) = 8.
But both A & B are tossing coins.
So, in our case, n (S) = 8^2 = 64.
Out of 8 sample points in a toss of 3 coins, 3 have 2 heads, 3 have 1 head, 1 has 3 heads & 1 has 0 heads.
Again, as tossing is performed by both A & B, firstly, we've to square the results obtained & then add them.
n (A) = 3^2 + 3^2 + 1^2 + 1^2
= 20.
Probability = 20/64 = 5/16.
S = { HHH, HHT, HTH, THH, TTH,
THT, HTT, TTT }
So, n(S) = 8.
But both A & B are tossing coins.
So, in our case, n (S) = 8^2 = 64.
Out of 8 sample points in a toss of 3 coins, 3 have 2 heads, 3 have 1 head, 1 has 3 heads & 1 has 0 heads.
Again, as tossing is performed by both A & B, firstly, we've to square the results obtained & then add them.
n (A) = 3^2 + 3^2 + 1^2 + 1^2
= 20.
Probability = 20/64 = 5/16.
nope
getting head and tail probability always 1/2
so for getting two heads, getting one head or getting no head ... the probability for each case will be 1/4*1/4
so in total the probability of the whole scenario is 3/16
and that's the answer
Answered by
0
Step-by-step explanation:
If both get one head then it is 1/4×1/4 and if both get two heads then it is 1/2×1/2
Prob (getting same number of heads)
1/4×1/4+1/2×1/2=1/16+1/4=5/16
I hope it help you
wrong answer
actually as getting head and tail ... probability will always be 1/2
so for two heads it's 1/4*1/4
for one head it's 1/4*1/4
for no heads it's 1/4*1/4
so the answer is 3/16 total
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