Question

Each of equal sides of an isosceles triangle is 2 cm greater than its height. If the base of the triangle is 12 cm, find the area of a triangle.

Please give correct answer.

Answer 1

Step-by-step explanation:

Solution :

Let ABC be an isosceles triangle with base BC = 12cm.

Let its height AD be x cm, then D is mid point of BC, therefore, BD = 6 cm.

According to the given :

AB = AC = (x + 2) cm.

From right angle ΔABD,

by Pythagoras theorem, we get

AB² = AD² + BD²

(x + 2)² = x² + 6²

x² + 4x + 4 = x² + 36

4x = 36 - 4

4x = 32

x = 32/4

x = 8.

Therefore :

Area of ΔABC = 1/2 × BC × AD

= 1/2 × 12 × 8 cm²

= 48 cm².

Hence :

Area of Δ ABC is 48 cm².

Answer 2

Step-by-step explanation:

Each of equal sides of an isosceles triangle is 2 cm greater than its height. If the base of the triangle is 12 cm, find the area of a triangle.

Please give correct answer.