Question

Each of equal sides of an isosceles triangle is
4 cm greater than its height. If the base of the
triangle is 24 cm; calculate the perimeter and
the area of the triangle.​

Answer 1

Let height of the triangle be x

Therefore,length of one of the equal sides is x+4

Area of triangle =1/2 × base × height

=1/2×24× x

=12x

perimeter = x+4 + x+4 + 24

=2x+8+24

=2x +32

Answer 2

Answer:

perimeter 64cm

area 240 sq. cm

Step-by-step explanation:

• let the height be x
• equal sides = x+4
• base =24/2=12
• according to pythagorus triplet
• (x+4)*2 =X×X+ 12×12
• X×X+8X+16=X×X+144
• 8X=144-16
• X=128/8
• X=16
• SO, Equal sides are 16+4=20
• Perimeter=20+20+24=64cm

area=1/2×24×20=240 sq.cm