Question

Each of equal sides of an isosceles triangle is
4 cm greater than its height. If the base of the
triangle is 24 cm; calculate the perimeter and
the area of the triangle.

pls tell it's urgent!!!!​

Answer 1

Correct option is

B

64cm;192cm

2

Let the congruent side of the isosceles triangle be a and the height be h.

Given a=h+4

Since the height of the triangle, divides it into two right angled triangles,

a

2

=h

2

+(

2

b

)

2

=>(h+4)

2

=h

2

+12

2

h

2

+16+8h=h

2

+144

8h=128

h=16cm

a=20cm

Perimeter of the triangle = Sum of all sides =a+a+b=20+20+24=64cm

Area of triangle =

2

1

× base × height =

2

1

×24×16=192 sq cm