Question

each of equal sides of an isosceles triangle is 4cm greater than its height. if the base of the triangle is 24cm , find its area and perimeter ​

Answer 1

Answer:

Let the congruent side of the isosceles triangle be a and the height be h.

Given a=h+4

Since the height of the triangle, divides it into two right angled triangles,

a

2

=h

2

+(

2

b

)

2

=>(h+4)

2

=h

2

+12

2

h

2

+16+8h=h

2

+144

8h=128

h=16cm

a=20cm

Perimeter of the triangle = Sum of all sides =a+a+b=20+20+24=64cm

Area of triangle =

2

1

× base × height =

2

1

×24×16=192 sq cm

Answer 2

Answer:

PERIMETER =32 CM

AREA =16 CM SQUARE