each of equal sides of isosceles triangle is 4 times the third side.the perimeter of the triangle is 117 cm .find the side of the triangle
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Let third side be x,
Each equal side = 4x
=================
Perimeter = sum of all sides
117 = x + 4x + 4x
117 = 9x
117/9 = x
13 = x
======================
unequal side =x= 13 cm
Each equal side = 4x =4(13) = 52 cm
i hope this will help you
(-:
Each equal side = 4x
=================
Perimeter = sum of all sides
117 = x + 4x + 4x
117 = 9x
117/9 = x
13 = x
======================
unequal side =x= 13 cm
Each equal side = 4x =4(13) = 52 cm
i hope this will help you
(-:
Answered by
2
Heya !!!
Let ∆ABC is an isosceles triangle.
In which,
AB = AC
And,
Let BC is X cm.
According to the,
Each equal sides = 4( Different side)
AB = AC = 4BC
AB = AC = 4X cm.
Perimeter of isosceles triangle = 117 cm
AB + AC + BC = 117
4X + 4X + X = 117
9X = 117
X = 117/9
X = 13 cm.
BC = X = 13 cm
And,
AC = AB = 4×13 = 52 cm
HOPE IT WILL HELP YOU..... :-)
Let ∆ABC is an isosceles triangle.
In which,
AB = AC
And,
Let BC is X cm.
According to the,
Each equal sides = 4( Different side)
AB = AC = 4BC
AB = AC = 4X cm.
Perimeter of isosceles triangle = 117 cm
AB + AC + BC = 117
4X + 4X + X = 117
9X = 117
X = 117/9
X = 13 cm.
BC = X = 13 cm
And,
AC = AB = 4×13 = 52 cm
HOPE IT WILL HELP YOU..... :-)
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