Question

Each of root of
${x}^{2} - bx + c = 0$
is decreased by 2.The resulting equation is
${x}^{2} - 2x + 1 = 0$
then,

✨HoLa Solve this Frnds✨

✨Advance Happy 2020​

Answer 1

Answer:

${x}^{2} - 2x + 1 \\ (x - 1)(x - 1)$

root of above equation is 1

so the new equation would be

$(x - 3)(x - 3) \\ {x}^{2} - 6x + 9$

comparing it with given equation

b = 6

c = 9

Answer 2

follow the correct answer