Each of the 2 bulbs takes 2A current at 50V supply. They r joined in series. How much resistance should be added in series with the lamp so that on connecting them with 120V supply, a current of 2A flows through each of them?
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R1 = V2/p1R2 = V2/p2R = R1+R2I = V/R=V/R1+R2p= I2(R1+R2)p=V2(R1+R2)2R1+R2 = V2(R1+R2)=1R1V2+R2V2=11p1+1p2p = p1p2p1+p2
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