Question

Each of the 2 equal sides of an isosceles triangle is twice as large as the third side. If the perimeter of the triangle is 210 cm, find the length of each side of the triangle

Answer 1

Step-by-step explanation:

Let an isosceles triangle have equal sides in length of 2x cm

So, x cm be the third side of the triangle

Perimeter of the triangle =30 cm

⇒ x+2x+2x=120

⇒ 5x=120

⇒ x= 120/5

⇒ x=24 cm

Therefore, the required sides of the isosceles triangle are 24 cm,48 cm,48 cm.

Answer 2

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Answer:

• Length of sides of the triangle = 84cm , 84cm and 42cm.

Given:

• Each of the 2 equal sides of an isosceles triangle is twice as large as the third side.
• The perimeter of the triangle is 210 cm.

To find:

• Find the length of each side of the triangle?

Let's understand:

Let the 2 equal sides of the isosceles triangle be 2x.

• Cause the length is twice larger then the third side.
• Let the third side be x .
• 2x is twice larger then x.

Solution:

The equation will be,

x + 2x + 2x = 210

• Add the x's.

5x = 210

• 5 is transposed to the other side.

$\sf x = \dfrac{210}{5}$

• Divide 210 by 5.

x = 42.

Therefore,

Sides of the triangle are:

• First side = 2x = (42 × 2)° = 84cm.
• Second side = 2x = (42 × 2)° = 84cm.
• Third side = x = 42cm.

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