Question

Each of the equal sides of an isosceles triangle is 4 cm greater than its height base is 24cm find the area

Answer 1

Take one of the equal sides of the triangle to be 'x'cm.Then, write an Expression with the information given in the question.

Base=24
draw an imaginary line for height.The triangle divides into 2 now.Then 24÷2=12cm for the base of one triangle. one side xcm That is the the hypotenuse.Use Pythagoras theorem to solve for x:
x^2=(x+4)^2+12^2
Now u found x cm.U can find the height now.
height=x +4 (according to the information given in the question)
finally, use the formula to find the area
1÷2 ×(b=24)×(h)= AREA

Answer 2

Answer:

Area = 192cm^2

Step-by-step explanation:

Base = 24cm

Height = xcm

(x+4)^2 = x^2 + (12)^2

x^2 + 8x + 16 = x^2 + (12)^2

8x = x^2 - x^2 + 144 - 16

8x = 128

x = 128/8

x = 16

Perimeter = 24 + 16+ 4 + 16 + 4

Perimeter = 64cm

Area = $\sqrt{s(s-a)(s-b)(s-c)}$

{S = 64/2 = 32 ; A = 24 ; B = 20 ; C = 20}

Area = $\sqrt{32(32-24)(32-20)(32-20)}$

Area = $\sqrt{32*8*12*12}$

Area = $\sqrt{8*4*8*12*12}$

Area = 8*2*12

Area = $192cm^{2}$