Chemistry, asked by suyfghv1129, 11 months ago

Each of the five struts consists of an aluminium tube that

Answers

Answered by antiochus
0

The allowable Loads P_{all} =2.64KN, 0.661KN, 10.57KN, 5.39KN, 2.64KN

Explanation:

consider the following conditions

C_{0} =\frac{1}{2} d_{0} =\frac{1}{2}(32)=16mm

C_{in} =C_{0} -t=16-4=12mm

I=\frac{\pi }{4} (C_{o} ^{4} -C^{4} _{i} )

=351858*10^{3} mm^{4}

=35.1858*10^{-4} m^{4}

\pi ^{2} EI=\pi ^{2} (70*10^{4} )(35.1858*10^{-4} )

=24309N-m^{2}

P_{cr} =\frac{\pi^{2}EI  }{Le^{2} } =\frac{24309}{Le^{2} }

First point

(1) L_{e} =(1)(2.0)=2.0m

P_{all} =2642N=2.64KN

(2) L_{e} =(2)(2.0)=4.0m

P_{all} =661N=0.661KN

(3) L_{e} =(\frac{1}{2} )(2.0)=1.0m

P_{all} =10569N=10.57KN

(4) L_{e} =(0.7)(2.0)=1.4m

P_{all} =5392N=5.39KN

(5) L_{e} =(1.0)(2.0)=2.0m

P_{all} =2642N=2.64KN

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