Question

each of the following determine whether the given value the solution of the given equation or not 2x²-x-1=0 ; x = 1​

Answer 1

Answer:

x = 1 is a solution of the given quadratic equation.

Step-by-step explanation:

Given quadratic equation,

2x² - x - 1 = 0

If 'α' is a solution of a quadratic equation p(x) = ax² + bx + c ; then p(α) = 0

So, put x = 1 and if the result is zero; it is a solution of the given equation.

⇒ 2(1)² - 1 - 1

⇒ 2(1) - 1 - 1

⇒ 2 - 2

⇒ 0

The result is zero. Hence x = 1 is a solution of the given quadratic equation.

 

Answer 2

"

x = 1 is the solution of the equation

Step-by-step explanation:

2x² - x - 1 = 0 ; x = 1

If we put the value of x (1) and we get the answer 0, then x = 1, is a solution of the equation.

2x² - x - 1 = 0

[put the value of x = 1]

=> 2(1)² - 1 - 1 = 0

=> 2(1) - 2 = 0

=> 2 - 2 = 0

=> 0 = 0

=> LHS = RHS

Hence x = 1 is the solution of quadratic equation 2x² - x - 1.

hope it helps.