Question

each of the following, find the remainder when p(x) is divided by g(x).

(i) p(x)=x²+x²+x²+x²+2x+2, g(x)=x²+1 (iii) p(x) = 4x12x² +14x-3, g(x)=x (m) p(x) = 3x - 4x -3x-1, g(x)=x-1

(iv) p(x)=x+3x² +10, g(x)=x²+1​

Answer 1

Answer:

2x−1=0⇒x=

2

1

.

By the remainder theorem, we know that when f(x) is by (2x−1), the remainder is f(

2

1

).

Now, f(

2

1

)=[4×(

2

1

)

3

−12×(

2

1

)

2

+14×

2

1

−3]

=(

2

1

−3+7−3)=

2

3

.