Question

Each of the height and radius of the base of a right circular cone is
creased by 10%. The volume of the cone be increased (in percent) by
(c) 44.2 (d) 100 (SSC 2010
1​

Answer 1

Answer:

Step-by-step explanation:

Solution :-

Volume of cone = πr²h/3

New radius = 11r/10

new height = 11h/10

So new V = π(11r/10)²)(11h/10)(1/3)

               = π(121r/100)(11h/10)(1/3)

                =  π 1331rh/3000

percentages increased = (new volume/old volume  × 100) -100

=> (π/3 × 3/π ×1331/1000 × rh/rh   × 100) -100

=> (1331/1000   × 100) -100

=> 133.1 -100

= > 33.1%

the value of the cone will be = 33.1%

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