Each of the six children -Amit, Sumit, Kamat, Namit, Ranjit and Charit has a different number of chocolates among 3, 4, 5, 6, 7 and 8 not necessanty in the same order. We know the following information.
1. The difference between the number of chocolates with Charit and Ranjit is the same as that between the number of chocolates with Kamat and Ranjit
II The number of chocolates with Charit is less than that with Sumit which in turn, is less than that with Ranjit
Ill The number of chocolates with Sumit is more than that with Namit
4 marks
O'marks
Section A
Section B
2
3
1
E
12
Leg
What is the number of chocolates with Sumit?
Answers
Step-by-step explanation:
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Answer:
The number of chocolates with Sumit = 4.
Step-by-step explanation:
Lets assume, number of chocolates with Amit = A, with Sumit = S, with Kamat = K, with Namit = N, with Ranjit = R and with Charit = C.
Chocolates are divided in the following numbers = {3, 4, 5, 6, 7, 8}
- The conditions given like:
(1) R - C = K - R
(2) C < S < R
(3) S > N
- From condition (1) we can say K > R > C and
from condition (2), R > S >C. and from condition (3) S > N
Comparing above two relations, K > R > S > C, N
As between R and C, S is there so R - C ≥ 2. Same thing will happen for K - R.
There must be another number between K and R and that number can be A.
- The arrangement can be expressed as, K > A > R > S > C, N.
The numbers are 8 > 7 > 6 > 5 > 4 > 3
∴ K = 8, A = 7, R = 6, S = 4, C and N can be 4 or 3
∴ The number of chocolates with Sumit = 4.
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