each of the two angles of a triangle is three-fourths of the third angle. find the three angles of a triangle .
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Answered by
2
Let the third angle be x.
Therefore
3/4x are the other two angles
Hence ,
3/4x+3/4x+x=180
Simplifying ,
10x=180x4
X=180x4/10= 72
Hence the angles are
72degrees , 54 degrees and 54 degrees
Hope this helps'
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Therefore
3/4x are the other two angles
Hence ,
3/4x+3/4x+x=180
Simplifying ,
10x=180x4
X=180x4/10= 72
Hence the angles are
72degrees , 54 degrees and 54 degrees
Hope this helps'
Pls mark as brainliest
Answered by
2
Let the third angle be x°
First angle = Second angle
So , their value is 3x/4
We know, three angles sum 180°
So , ⇒ x + 3x/4 + 3x/4 = 180
⇒10x/4 = 180
⇒10x = 180 * 4
⇒x = 720 /10 = 72
∴Third angle = x = 72 °
First and second angles = 3x/4 = 3*72/4 = 54
Answer : First angle = 54 ° , Second angle = 54° , Third angle = 72°
SnehalD:
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