Each of the two equal angles of a triangle is 10 more than 1/2 of the third angle. Find the angles of the triangle.
Answers
Answered by
4
a=1/2 of b + 10
2a=b +20
2a+b= 180
b+20+b=180
2b=160
b=80
each equal angle, a=50
2a=b +20
2a+b= 180
b+20+b=180
2b=160
b=80
each equal angle, a=50
Answered by
4
Equal angles = x°
Third angle = 180° - 2 x°
Given x = (180° -2 x)/2 + 10°
So x = 50°
Third angle = 80°
Third angle = 180° - 2 x°
Given x = (180° -2 x)/2 + 10°
So x = 50°
Third angle = 80°
Similar questions