Question

each of the two equal angles of a triangle is twice the third angle .find the angles of the triangle​

Answer 1

Answer:

let the 1st and second angle of triangle=X

the 3nd angle of triangle=2x

X +X+2x =180°

4x=180°

X =180°÷4

=45°

3rd angle 2x

= 2×45

=90°

1st angle =45°

2nd angle= 45°

3rd angle= 90°

Step-by-step explanation:

Answer 2

Answer:

45,45,90

Step-by-step explanation:

sum of all angles =180

let one angle =x

x+x+2x=180

4x=180

x=45

2x=90

check

45+45+90

=180