Question

each of the two equal angles of a triangle is twice the third angle. find the angles of the triangle ?​

Answer 1

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Hey yours answer is here

Let the 1st and the 2nd angle is 2x

now the third one is x

A.T.Q.

2x+2x+x=180

5x=180

x= 180/5

now the third side is 36°

and the first and second is

2x=>2×36=72°

Answer 2

Given :

⬤ Each of two angles of a Triangle is twice the third Angle .

To Find :

⬤ Angles of Triangle .

Solution :

Let :

• Third Angle be = x .

As given that , Each of two equal angles of a triangle is twice the third Angle . Hence ,

• First Angle = 2x .
• Second Angle = 2x .

As we know that , Sum of all angles of Triangle is 180 degree . Hence ,

$\sf{2x+2x+x=180^{\circ}}$

5x = 180°

x = 180/5

x = 36

Therefore , The Value of x is 36 .

Hence ,

First Angle = 2x

= 2(36)

= 72

Second Angle = 2x

= 2(36)

= 72

Third Angle = x

= 36

Therefore , The three Angles of Triangle is 72° , 7°2 and 36° .