each of the two equal angles of a triangle is twice the third angle. find the angles of the triangle
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Let the measure of third angle be x
According to the question, each of the remaining two angles are twice of x.
Third angle = x
Each equal angle = 2x
Sum of all angles of a triangle = 180°
x + 2x + 2x = 180°
5x = 180°
x= 180/5
x = 36°
Therefore, third angle = x = 36° and each equal angle = 2x = 2( 36° ) = 72°
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