each of the two equal angles of an isosceles triangle is twice and third find the angles of triangle
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let the third angle =x
the two equal angles r =2x each
so 2x+2x+x=180
5x=180
x=180/5
x=36
so the angles are 36 degrees and the equal angles are 36*2=72 degrees
the two equal angles r =2x each
so 2x+2x+x=180
5x=180
x=180/5
x=36
so the angles are 36 degrees and the equal angles are 36*2=72 degrees
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x+x+ third angle=180°(sum of angle of triangle)
2x+third angle=180°
X+third angle/2=90°
Third angle=(90-x)2
2x+third angle=180°
X+third angle/2=90°
Third angle=(90-x)2
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