Each of the two equal sides of a triangle are 4 m less than three times the third side.find the dimensions of the triangle, if its Perimeter is 55m.
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let the third side of triangle be x m
according to question,second and first sides are 4 less than 3 times of third side.
so,1st and 2nd side = 3x-4
perimeter of triangle = sum of three sides
= 3x-4+3x-4+x=55
= 3x+3x+x-4-4=55
=7x-8=55
=7x=55+8
=7x=63
=x=63/7
=x=9 m
so third side = 9 m
first and second sides are = 3×x-4=3×9-4
=27-4=23 m
therefore the dimensions of triangle are 23 m,23 m and 9 m
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