Question

Each of the two equal sides of a triangle
is 4 m less than three times the third
side. Find the sides of the triangle, if its
perimeter is 55 m.
​

Answer 1

Answer:

Let be 3rd side=x

1st side =2nd side =3x-4

According to qiestion

x+3x-4+3x-4=55

7x=55+4+4

7x=63

x=9

hence:

1st side =3×9-4=23m

2nd side =23m

3rd side =9m

Answer 2

Answer:

9cm,23cm,23cm

Step-by-step explanation:

Let us take the unknown lenth of third side be xm

So as per given ,

Let the other two equal sides be 3x-4 m

Perimeter =55m

Perimeter of triangle = Sum of three sides

55=x+(3x-4) +(3x-4)

55=x+2(3x-4)

55=x+6x-8

55=7x-8

7x=63

x=9

Therefore one side is 9cm

and other two sides are 3×9-4=27-4=23cm

Hope it helps u out