Question

Each of the two equal sides of an isosceles triangle is thrice as large as the third side. If the perimeter of the triangle is 35 cm find the length of each side of the triangle

no irreverent answers please ​

Answer 1

Step-by-step explanation:

Given :

• Each of the two equal sides of an isosceles triangle is thrice as large as the third side.
• The perimeter of the triangle is 35 cm.

To Find :

• The length of each side of the triangle.

Solution :

★ Given that,

• Two sides are of equal length and are thrice as large as the third side

★ Let's assume that,

• Third side = x

★ So, the other two equal sides,

• 3x and 3x

★ Perimeter of triangle = Sum of all sides ★

Putting all the values,

$\sf \longrightarrow \: Perimeter_{(Triangle)} = x + 3x + 3x$

$\sf \longrightarrow \: 35 = x + 3x + 3x$

$\sf \longrightarrow \: 35 = x + 6x$

$\sf \longrightarrow \: 35 = 7x$

$\sf \longrightarrow \: \dfrac{35 }{7}= x$

$\sf \longrightarrow \: \cancel\dfrac{35 }{7}= x$

$\red{\sf \longrightarrow \: \underline{ \boxed{ \bf5 \: cm= x} } \: \bigstar}$

So, value of x is 5.

~Finding the sides,

• x = 5 cm
• 3x = 3(5) = 15 cm
• 3x = 3(5) = 15 cm

Hence, the sides of the triangle are 5 cm, 15 cm and 15 cm respectively.

Answer 2

Answer:

35

Step-by-step explanation:

3rd sid_x

Each equal side-3x

P=3x+3x+x=7x

7x=35

x=35÷7=5

Equal sides=5×3=15

15+15+5=35