Question

Each of the two sides of an isosceles triangle is 1cm less than the third.if its perimeter is 16cm,find the sides of the triangles...(explain in derail with correct method)​

Answer 1

Answer

∴ Perimeter = 16

∴ Perimeter = 16∴(x−1)+(x−1)+x=16

∴ Perimeter = 16∴(x−1)+(x−1)+x=163x - 2 = 16

∴ Perimeter = 16∴(x−1)+(x−1)+x=163x - 2 = 163x = 18

∴ Perimeter = 16∴(x−1)+(x−1)+x=163x - 2 = 163x = 18x = 6 cm

∴ Perimeter = 16∴(x−1)+(x−1)+x=163x - 2 = 163x = 18x = 6 cmAB = AC = 5cm , BC =6cm

Answer 2

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Given:

• Equal sides of isosceles triangle are 1cm less than the third.
• Perimeter is 16cm

To Find:

• The sides of the triangle

Solution:

Let the equal sides be x.

So, the third side is x+1.

Perimeter = 16cm

=> 16cm = x + x + x + 1

=> 16cm = 3x + 1

=> 16 - 1 = 3x

=> 3x = 15

=> x = 5.

The sides of the triangle are => 5cm, 5cm and 6cm.

HOPE IT HELPS!!