Question

Each of the uncharged capacitors in the figure has a capacitance of 35.5 μF. A potential
difference of 4200 V is established when the switch is closed. How much charge then passes
through meter A

Answer 1

Answer:

1491×10^-4C

Explanation:

Let charge be Q

C=Q/V

C=35.5×10^-6

V=4200v

Q=4200×35.5×10^-6

=1491×10^-4

Q=1491×10^-4C