Question

Each of three bulbs having same resistance can dissipate maximum power Po. The maximum power, the circuit of three bulbs can dissipate is​

Answer 1

Explanation:

By using Ohm's law,

V=IR,

where,

V= voltage across a resistor

I = current through the resistor

R = value of resistance.

The power dissipated by the resistor is given by P=

R

V

2

=I

2

R

thus I

2

=

R

P

Each resistance dissipates energy = 18 Watts

The maximum current through B or C or A is given by I

2

=

2 ohms

18 Watts

So I=3 Amperes maximum

Since the resistances B and C are connected in parallel, the current that comes from the resistance A is divided equally between the resistance B and C.

so current through B = current through resistance C =

2

1

× current through A

Since, the current passing thru resistor A is max = 3 amperes, then the current through resistor B and resistor C is 1.5 Amperes maximum